Maths

Taylor Series Of Ln1x

Understanding the Taylor Series for ( \ln(1+x) )

The Taylor series is a powerful mathematical tool used to represent functions as infinite sums of terms calculated from the values of their derivatives at a single point. For the natural logarithm function ( \ln(1+x) ), the Taylor series expansion provides a convenient way to approximate the function near ( x = 0 ).

Deriving the Taylor Series for ( \ln(1+x) )

To derive the Taylor series for ( \ln(1+x) ), we begin by determining the function’s derivatives at the point ( x = 0 ). The first derivative of ( \ln(1+x) ) is given by:

[
\frac{d}{dx} \ln(1+x) = \frac{1}{1+x}
]

Evaluating this derivative at ( x = 0 ):

[
f'(0) = \frac{1}{1+0} = 1
]

The second derivative is:

[
\frac{d^2}{dx^2} \ln(1+x) = -\frac{1}{(1+x)^2}
]

Evaluating at ( x = 0 ):

[
f”(0) = -1
]

Continuing, the third derivative is:

[
\frac{d^3}{dx^3} \ln(1+x) = \frac{2}{(1+x)^3}
]

Evaluated at zero gives:

[
f”'(0) = 2
]

Following this pattern, the nth derivative can be generally expressed as:

[
f^{(n)}(x) = (-1)^{n-1} (n-1)! \cdot \frac{1}{(1+x)^n}
]

Thus, by evaluating at ( x = 0 ), we find:

[
f^{(n)}(0) = (-1)^{n-1} (n-1)!
]

According to Taylor’s theorem, the Taylor series expansion around ( x = 0 ) is given by:

[
f(x) = f(0) + f'(0)x + \frac{f”(0)}{2!}x^2 + \frac{f”'(0)}{3!}x^3 + \ldots
]

Substituting the derivative values, and noting that ( f(0) = \ln(1+0) = 0 ), we obtain:

[
\ln(1+x) = x – \frac{x^2}{2} + \frac{x^3}{3} – \frac{x^4}{4} + \ldots = \sum_{n=1}^{\infty} \frac{(-1)^{n+1} x^n}{n}
]

This series converges for ( -1 < x \leq 1 ), providing a means to estimate ( \ln(1+x) ) for values within this interval.

Convergence of the Series

The convergence of the Taylor series for ( \ln(1+x) ) can be analyzed via the ratio test or other convergence tests. The series converges absolutely for ( |x| < 1 ) and converges conditionally at ( x = 1 ). At this point, the series diverges at ( x = -1 ).

See also  Divisors of 63

Applications of the Taylor Series

The Taylor series expansion of ( \ln(1+x) ) has various applications in mathematics, engineering, and physics. It allows for simplified calculations when ( x ) is small, making it easier to compute values of the logarithm without needing a calculator. Furthermore, it plays a crucial role in numerical methods for solving integrals and differential equations, providing a standard approach for approximating logarithmic functions.

Frequently Asked Questions

What is the interval of convergence for the Taylor series of ( \ln(1+x) )?

The Taylor series for ( \ln(1+x) ) converges in the interval ( -1 < x \leq 1 ). It converges absolutely for ( |x| < 1 ) and converges conditionally at ( x = 1 ).

Can the Taylor series be used to evaluate ( \ln(1+x) ) for all values of ( x )?

The Taylor series is a valid representation of ( \ln(1+x) ) only within the specified interval of convergence. For values of ( x ) outside this range, alternative methods or series would be needed.

How is the Taylor series of ( \ln(1+x) ) useful in practical applications?

The Taylor series allows for quick approximations of ( \ln(1+x) ) values when ( x ) is near zero, making it a valuable tool in computational mathematics, particularly in numerical analysis and problem-solving within physics and engineering contexts.